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The binding energies per nucleon for deuteron (._1H^2) and helium (._2He^4) are 1.1 MeV and 7.0 MeV respectively. Calculate the energy released, when two deuterons fuse to form a helium nucleus. |
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Answer» Solution :Thefusion reaction is `2(""_(1)H^(2)) rarr ""_(2)He^(4)+Q` Q = TOTAL binding energy of the product `""_(2)He^(4)` - Total binding energy of REACTANT i.e. , two DEUTERONS. `= 4 xx7.0 - 4 xx 1.1 = 28.0 - 4.4` = 23 . 6 MEV |
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