The binding energy of an electron in the ground state of He atom is E_(0)=24.7eV. The energy required to remove both the elements from the atom is

The binding energy of an electron in the ground state of He atom is E_

1.	The binding energy of an electron in the ground state of He atom is E_(0)=24.7eV. The energy required to remove both the elements from the atom is
Answer» 24.6eV 79.0eV 54.4eV None of these Solution :The total energy required to MAKE the ELECTRON free from nucleus is the SUM of the energy required to separate the ELECTRONS from the influence of each other and the energy required to separate the electrons from the influence of nucleus,i.e., Total required energy = BE of electron in He ATOM + ionization energy of He atom `= (24.6+13.6xx2^2)eV` `=(24.6 +54.4)e V =79eV`

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The binding energy of an electron in the ground state of He atom is E_(0)=24.7eV. The energy required to remove both the elements from the atom is

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