1.

The binding energy per nucleon for deuteron (""_(1)^(2)H)" helium "(""_(2)^(4)He) are 1.1MeV and 7.0 MeV. The energy released when deuterons fuse to form a helium nucleus is:

Answer»

2.3 MeV
23.6MeV
28.0MeV
30.2MeV

Solution :B.E. of `4/2 He=7 xx 4=28.0MeV`
`B.E. of ""_(1)^(2)H=1.1 xx 2=2.2 MeV`
ENERGY RELEASED `=29.0-(2 xx 2.2) =23.6 MeV`


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