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The block C shown in the figure is ascending with an acceleration a=3m//s^(2) by means of some motor not shown here. Find the acceleration of the bodies A and B of masses 10 kg and 5kg respectively in m//s^(2), assuming pulleys are massless and friction is absent everywhere. |
Answer» SOLUTION :Drawing F.B.D. diagrams. `10g-2T=10a_(A)``(1)` `5g-T=5a_(B)``(2)` `T` from EQUATIONS `(1)` & `(2)` we GET `10a_(A)-10a_(B)=0` `rArr a_(A)=a_(B)` `l_(1)+l_(2)+l_(3)=`constant `y_(E)+y_(A)+y_(A)+y_(B)=` costant Differentiating twice w.r.t. time, `a+2a_(A)+a_(B)=0` `2a_(A)+a_(B)=-3` or `3a_(0)= -3` `rArr a_(B)=-1m//s^(2)`, `a_(A)=-1m//s^(2)` `a_(A)=a_(B)=1m//s^(2)` upwards |
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