InterviewSolution
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InterviewSolution
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The block of mass `M` moving on the frictionless horizontal surface collides with the spring constant `k` and compresses it by length `L` . The maximum momention of the block after collision isA. `(kL^(2))/(2 M)`B. `sqrt(Mk) L(c )`SC. `(ML^(2))/(k)`D. zero |
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Answer» Correct Answer - B (b) `(1)/(2) M nu^(2) = (1)/(2) k L6(2) rArr nu = sqrt(k)/(M) . L` Momentum `= M xx nu = M xx sqrt (k)/(M). L = sqrt(kM) . L` |
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