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The Bohr radius of the innermost orbit of a hydrogen atom is 5.3xx10^-11m.What are the radii of n=2 and n=3 orbits? |
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Answer» SOLUTION :`r_n=n^2r_1 ` `THEREFORE r_2=2^2r_1=4xx5.3xx10^(-11)=21.2xx10^(-11)m` ` r_3=3^2r_1=9xx5.3xx10^(-11)=47.7xx10^(-11)m` |
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