The boiling point elevation and the freezing point depression of solutions have a number of practical applications. Ethylene glycol (CH_(2)OH. CH_(2)OH) is used in automobile radiators as an antifreeze because it lowers the freezing point of the coolant. The same substance also helps to prevent the radiator coolant from boiling away by elevating the boiling point. Ethylene glycol has low vapour pressure. We can also use glycerol as antifreeze. For the boiling point elevation to occur the solute must be non-volatile, but no such restriction applies to freezing point depression. For example mthanol (CH_(3)OH), a fairly volatile liquid that boils only at 65^(@)C is sometimes used as antifreeze in automobile radiators. 620g glycol is added to 4kg water in the radiator of a car. What amount of ice will separate out at -6^(@)C ? K_(f) = 1.86K kg mol^(-1).

The boiling point elevation and the freezing point depression of solut

1.	The boiling point elevation and the freezing point depression of solutions have a number of practical applications. Ethylene glycol (CH_(2)OH. CH_(2)OH) is used in automobile radiators as an antifreeze because it lowers the freezing point of the coolant. The same substance also helps to prevent the radiator coolant from boiling away by elevating the boiling point. Ethylene glycol has low vapour pressure. We can also use glycerol as antifreeze. For the boiling point elevation to occur the solute must be non-volatile, but no such restriction applies to freezing point depression. For example mthanol (CH_(3)OH), a fairly volatile liquid that boils only at 65^(@)C is sometimes used as antifreeze in automobile radiators. 620g glycol is added to 4kg water in the radiator of a car. What amount of ice will separate out at -6^(@)C ? K_(f) = 1.86K kg mol^(-1).
Answer» 800g 900g 600g 1000g Answer :B