1.

The boiling point of a solution of 0.11 of a substance in 15g of ether was found to be 0.1^(@)C higher than that of pure ether. The molecular weight of the substance will be (K_(b)=2.16) :

Answer»

148
158
168
178

Solution :`m=(K_(B)XX W xx1000)/(Delta T_(b)xx W)`
`K_(b)=2.16, w=0.11, W=15 g, Delta T_(b) =0.1`
`m=(2.16xx0.11xx1000)/(0.1xx15)=158.40 ~= 158`.


Discussion

No Comment Found

Related InterviewSolutions