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The boiling point of benzene is 353.23 K. When 1.80 g of a non - volatile non - ionisable solute was dissolved in 90 g of benzene, the boiling point raised to 354.11 K. |
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Answer» Solution :Given `T_(b)^(0)=353.2,""w_(2)=1.80g,""w_(1)=90G,""T_(b)=354.11K,""K_(b)=2.54"K Kg mol"^(-1)` `M_(2)=(K_(b)xxw_(2)xx1000)/(DeltaT_(b)xxw_(1))=(2.53xx1.8xx1000)/(0.88xx9)="58 g/mol"` |
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