1.

The boiling point of solution containing 68.4 g of sucrose ("molar mass" = 342 g mol^(-1)) in 100 g of water is (K_(b) "for water" = 0.512 K. kg mol^(-1))

Answer»

`100.02^(@)C`
`98.98^(@)C`
`101.02^(@)C`
`100.512^(@)C`

Solution :`DELTA T_(b) = K_(b) XX m = K_(b) xx W_(2)/(M_(2) xx W_(1) (kg))`
`=0.512 xx 68.4/(342 xx 0.1) = 1.024 ^(@) C `
` :. T_(b) = T_(b)^(o) + Delta T_(b) =100 ^(@) C + 1.024^(@)C=101.024^(@)C`


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