Saved Bookmarks
| 1. |
The boliling point of 5% solution (W/W) of non-volatile solute in water is 100.45^(@)C. The boiling point of pure water is 100^(@)C.Calculate th molar mas of th solute (K_(b)"for water=0.52 K kg mol"^(-1)). |
|
Answer» `W_(B)=5G, W_(A)=100-5=95g, 0.095 KG, K_(b)=0.52" K kg mol"^(-1)` `M_(B)=(K_(b)xxW_(B))/(DeltaT_(b)xxW_(A))=((0.52K" kg mol"^(-1))XX(5g))/((0.45K)xx(0.095 kg))=60.8" g mol"^(-1)`. |
|