1.

The bond angle in H_2O (for H-S-H) is

Answer»

same as that of Cl-Be-Cl in `BeCl_2`
greater than H-N-H bond angle in `NH_3`
greater than H-Se-H and less than H-O-H
same as Cl-Sn-Cl in `SnCl_2`

SOLUTION :The bond angle in `BeCl_2=180^@` , in `NH_3=107^@`, in `H_2O=104.5^@`, in `SnCl_2=119^@`
WHEREAS that of
is close to `90^@`


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