Saved Bookmarks
| 1. |
The bond distance between H-atom in H_(2) and X-atoms in X_(2) is 74 pm and 124 pm respectively. Find distance between H and X in HX electronegativity (EN) of H is 2.1 and X is 3.1 in pauling scale. Use Stevenson-Schomaker formula. [Divide your answer by 10] |
|
Answer» Solution :`d_(H-X)=r_(H)+r_(X)-0.09|r_(X)+r_(H)|` where `r_(H) & r_(X)` PUT in `overset(@)A` unit. `d_(H-X)=37xx10^(-2)+62xx10^(-2)-0.09xx1=0.99` `0.09=0.90 overset(@)A=90pm` `=(90)/(10)=9` |
|