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The bond energies of `H--H` , `Br--Br` and `H--Br` are `433,, 192` and `364KJmol^(-1)` respectively. The `DeltaH^(@)` for the reaction `H_(2)(g)+Br_(2)(g)rarr2HBr(g)` isA. `-261kJ`B. `+103kJ`C. `+261kJ`D. `-103kJ`d |
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Answer» The given reaction is: `H-H(g)+Br-Br(g)to2H-Br(g)` `DeltaH^(@)=sum(B.E.)_("Reactants")-sum(B.E.)_("products")` `=[433+192]-[2xx364]` `=-103kJ" "mol^(-1)` |
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