1.

The bond energies of `H--H` , `Br--Br` and `H--Br` are `433,, 192` and `364KJmol^(-1)` respectively. The `DeltaH^(@)` for the reaction `H_(2)(g)+Br_(2)(g)rarr2HBr(g)` isA. `-261kJ`B. `+103kJ`C. `+261kJ`D. `-103kJ`d

Answer» The given reaction is:
`H-H(g)+Br-Br(g)to2H-Br(g)`
`DeltaH^(@)=sum(B.E.)_("Reactants")-sum(B.E.)_("products")`
`=[433+192]-[2xx364]`
`=-103kJ" "mol^(-1)`


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