1.

The bond energies of `H--H` , `Br--Br` and `H--Br` are `433,, 192` and `364KJmol^(-1)` respectively. The `DeltaH^(@)` for the reaction `H_(2)(g)+Br_(2)(g)rarr2HBr(g)` isA. `- 261 kJ`B. `+ 103 kJ`C. `+ 261 kJ`D. `- 103 kJ`

Answer» Correct Answer - D
If the reaction is carried out in the gas phase only then the reaction enthalpy `(Delta_(r) H^(@))` can be calculated by the following relationship:
`Delta_(r) H^(@) = sum "Bond enthalpies"_("reactants") - sum "Bond enthalpies"_("product")`
` = [Delta_(H - H) H^(@) + Delta_(Br - BR) H^(@)] - (2 Delta_(H - Br)H^(@))`
`(433 + 192) - (2) (364)`
`= (625) - (728) = - 103 kJ mol^(-1)`


Discussion

No Comment Found

Related InterviewSolutions