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The bond energies of `H--H` , `Br--Br` and `H--Br` are `433,, 192` and `364KJmol^(-1)` respectively. The `DeltaH^(@)` for the reaction `H_(2)(g)+Br_(2)(g)rarr2HBr(g)` isA. `- 261 kJ`B. `+ 103 kJ`C. `+ 261 kJ`D. `- 103 kJ` |
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Answer» Correct Answer - D If the reaction is carried out in the gas phase only then the reaction enthalpy `(Delta_(r) H^(@))` can be calculated by the following relationship: `Delta_(r) H^(@) = sum "Bond enthalpies"_("reactants") - sum "Bond enthalpies"_("product")` ` = [Delta_(H - H) H^(@) + Delta_(Br - BR) H^(@)] - (2 Delta_(H - Br)H^(@))` `(433 + 192) - (2) (364)` `= (625) - (728) = - 103 kJ mol^(-1)` |
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