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The bond order in `O_2^+` is the same as in :A. `N_2^+`B. `CN^-`C. `CO`D. `NO^+` |
Answer» Correct Answer - A B.O. of `N_2^+=1/2[N_b-N_a]=1/2[5-0]=2.5` B.O. of `O_2^+=1/2[N_b-N_a]=1/2[6-1]=2.5` |
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