InterviewSolution
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InterviewSolution
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The bond order in `O_2^+` is the same as in :A. `N_(2)^(+)`B. `CN^(-)`C. `CO`D. `NO^(+)` |
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Answer» Correct Answer - A `O_(2)^(+) (15e^(-))=K: K^(**)(sigma2s)^(2)(sigma^(**)2s)^(2)(sigma^(**)2s)^(2)(sigma2p_(x))^(2)` `(pi 2 p_(y))^(2)(pi 2p_(z))^(2)(pi^(**)2p_(y))^(1)(pi^(**)2p_(z))^(0)` Hence, bond order =`1/2(10-5) =2.5` `N_(2)^(+) (13e^(-))=KK^(**) (sigma2s)^(2)(sigma^(**)2s)^(2)(sigma2p_(x))^(3)` `(pi 2p_(y))^(2)(pi 2p_(z))^(1)` Hence bond order =`1/2(9-4) =2.5` |
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