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The bond order of a molecule in the excited state can beA. positiveB. negativeC. zeroD. both (2) and (3) |
Answer» Correct Answer - B In the excited state, electrons are promoted to higher energy levels. Thus, `N_agtN_b` and bond order `(N_b-N_a)//2` becomes negative. It implies that the molecule is unstable. |
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