InterviewSolution
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InterviewSolution
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The bond order of `O_(2)` and `O_(2)^(+)` are _________ respectively.A. 2B. 1.5C. 3D. 3.5 |
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Answer» Correct Answer - A Electronic configuration of `O_(2)` is `O_(2)=(sigma1s)^(2)(sigma^(**)1s)^(2)(sigma2s)^(2)(sigma^(**)2s)^(2)(sigma^(**)2s)^(2)(sigma2p_z)^(2)` `(pi2p_(x)^(2)-=pi2p_(y)^(2))(pi^(**)2p_(x)^(1)-=pi^(**)2p_(y)^(1))` Hence bond order `=1/2[N_(b)-N_(a)]=1/2[10-6]=2` |
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