1.

The bonds is K_(4)[Fe(CN)_(6)] are

Answer»

all IONIC
all covalent
ionic, covalent and coordinate
ionic and covalent.

Solution :Ionic bond between `4K^(+)` and `[Fe(CN)_(6)]^(4-)` coordinate bond between `Fe^(2+)` and `6CN^(-)` covalent bond between C and N to form `C-=N^(-)`


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