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The breaking stress of a cylindrical rod is 10^6 N/m^2. If the maximum possible height of the rod is 10 m then what is the density of the material of the rod ? |
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Answer» Solution :BREAKING stress = `F//A = (mg)/A = (Vrhog)/A` `= (A hrhog)/A = hrhog` `THEREFORE RHO = "Breaking stress"/(hg) = 10^6/(10 xx 10) = 10^4 (KG)/m^3` |
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