InterviewSolution
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InterviewSolution
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The bromination of acetone that occurs in acid solution is represented by this equation. `CH_(3)COCH_(3) (aq) + Br_(2) (aq) rarr` `CH_(3)COCH_(2) Br(aq) + H^(+) (aq) + Br(aq)` These kinetic data were obtained for given reaction concentrations. Initial concentration, `M` `{:([CH_(2)COCH_(3)],[Br_(2)],[H^(+)],("Initail rate) (disappearance of "Br_(2)),),(0.30,0.05,0.05,5.7 xx 10^(-5),),(0.30,0.10,0.05,5.7xx10^(-5),),(0.30,0.10,0.10,1.2xx10^(-4),),(0.40,0.5,0.20,3.1xx10^(-4),):}`A. `rate =K [CH_(2) COCH_(3)][H^(+)]`B. `rate= K [CH_(2)= COCH_(3)[Br_(2)]`C. `rate= K[CH_(3)COCH_(3)][Br_(2)][H^(+)]^(2)`D. `rate = k [CH_(3)COCH_(3)][BR_(2)][H^(+)]` |
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Answer» Correct Answer - A Let the order of reaction wrt `CH_(3)COOCH_(3) .Br_(2) and H^(+) are x,y,and z ` respectively thus . `Rate (I) =[CH_(3)COCH_(3)]^(x)[Br_(2)]^(y)[H^(+)]^(z) ` `4.7xx10^(-5)=(0.30)^(x)(0.05)^(y)(0.05)^(z)` `5.7xx10^(-5)=(0.30^(x)(0.10)^(y)(0.05)^(z)` `1.2xx10^(-4)=(0.30)^(x)(0.10)^(y)(0.10)^(z)` `3.1xx10^(-4)=(0.40)^(x)(0.05)^(y)(0.20)^(z)` from Eqs (i) and(ii) `1=((1)/(2))^(y)or 1^(@)=((1)/(2))^(y)` `y=0` from Eqs(ii) and (iii) `z=1` from Eqs.(i) and (iv) `x=1` thus rate law`prop |CH_(2)COCH_(3)|^(1)|Br_(2)|^(0)[H^(+)]^(1)` `=K[CH_(3)COCH_(3)][H^(+)]` |
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