The built in capacitance V0 for a step graded PN junction is 0.75V. Junction capacitance Cj at reverse bias when VR=1.25V is 5pF. The value of Cj when VR=7.25V is?(a) 0.1pF(b) 1.7pF(c) 1pF(d) 2.5PfThis question was addressed to me in my homework.I'd like to ask this question from Diode Capacitances in portion Semiconductor-Diode Characteristics of Electronic Devices & Circuits

The built in capacitance V0 for a step graded PN junction is 0.75V. Ju

1.	The built in capacitance V0 for a step graded PN junction is 0.75V. Junction capacitance Cj at reverse bias when VR=1.25V is 5pF. The value of Cj when VR=7.25V is?(a) 0.1pF(b) 1.7pF(c) 1pF(d) 2.5PfThis question was addressed to me in my homework.I'd like to ask this question from Diode Capacitances in portion Semiconductor-Diode Characteristics of Electronic Devices & Circuits
Answer» The correct OPTION is (d) 2.5Pf To EXPLAIN: We KNOW, Cj1/ Cj2=[(V0+VR2)/(V0+VR2)]^1/2 So, Cj2=Cj1/ {(0.75+7.25)/(0.75+1.25)}^1/2we GET Cj2=Cj1 /2 =5/2=2.5Pf.

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