1.

The capacitance of a capacitor is 4muF and its potential is 100 V. The energy released on discharging it fully will be

Answer»

0.02 J
0.04 J
0.025 J
0.05 J

Solution :Energy relased on fully discharging the charged CAPACITOR will be :
`u = 1/2 CV^2 = 1/2 (4 MUF) xx (100 V)^2 = 1/2xx 4 xx 10^(-6) xx 100 xx 100 xx 2 xx 10^(-2) J = 0.02J`


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