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The capacitance of a parallel plate capacitor formed by the circular plates of diameter 4.0 cm is equal to the capacitance or a sphere of diameter 200 cm. Find the distance between two plates. |
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Answer» `2xx10^(-4)` m `:. C_(1)= 4pi epsilon_(0)` R The capacitance of a parallel plate capacitor `C_(2)=(epsilon_(0)A)/(d)` but `C_(1)=C_(2)` `:. 4 PI in_(0)R = (epsilon_(0)pir^(2))/(d)` `:. D=(r^(2))/(4R)` but `r= 2.0 cm =2xx10^(-2)` m R = `(200)/(2) = 100 cm = 1 m` `:. d = (4xx10^(-4))/(4xx1)` `:. d = 1 xx10^(-4)` m |
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