1.

The capacitor of capacitance C can be charged (with the help of a resistance R) by a voltage source V, by closing switch S_(1) while keeping switch S_(2) open.The capacitor can be connected in series with an series with an inductor L by closing switchS_(2) and opening S_(1). Initially the capacitor was uncharged.Now switch S_(1) is closed and S_(2) is kept open.If time constant of this circuit is t, then

Answer»

after TIME INTERVAL `t`, charge on the CAPACITOR
after time interval `2pi`,charge on the capacitor is
N//A
N//A

Solution :`Q=Q_(0)(1-e^(-t//tau))`
`Q=CV(1-e^(-t//tau))` after time interval `2TAU`.


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