1.

The capacitor of capacitance C can be charged (with the help of a resistance R) by a voltage source V, by closing switch S_(1) while keeping switch S_(2) open.The capacitor can be connected in series with an series with an inductor L by closing switchS_(2) and opening S_(1). After the capacitor gets fully charged S_(1) is opened and S_(2) is closed so that the inductor is connected in series with the capacitor.Then

Answer»

at `t=0`,energy stored in the circuit is purely in the form of MAGNETIC energy
at any TIME `t gt 0`,current in the circuit is in the same direction
at `t gt 0`,there is no exchange of energy between the inductor and capacitor
at any time `t gt 0` instanteous curren in the circuit will have maximum vlaue `Vsqrt(C/L)` ,where `C` is the capacitance and `L` is the inductance.

Solution :`q=Q_(0)cos omegat`
`i=-(dq)/(dt)=Q_(0) omega sin omegat`
`RARR i_(max)=Comega V=Vsqrt(C/L)`


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