The capacitors in figure are initially uncharged and are connected as in the diagram with switch S open. The applied potential difference is V_(ab)= 360 V. In the given circuit diagram, find the charge which will flow through direction 1 and 2 when switch S is closed.

The capacitors in figure are initially uncharged and are connected as

1.	The capacitors in figure are initially uncharged and are connected as in the diagram with switch S open. The applied potential difference is V_(ab)= 360 V. In the given circuit diagram, find the charge which will flow through direction 1 and 2 when switch S is closed.
Answer» `q_(1)=EC_(2),q_(2)=-(EC_(1)C_(2))/((C_(1)+C_(2)))` `q_(1)=EC_(1),q_(2)=-(EC_(2)C_(1))/((C_(1)-C_(2)))` `q_(1)=EC_(1),q_(2)=-(EC_(2))/((C_(1)+C_(2)))` `q_(1)=EC_(1),q_(2)=-(EC_(2))/((C_(1)+C_(2)))` Answer :A

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The capacitors in figure are initially uncharged and are connected as in the diagram with switch S open. The applied potential difference is V_(ab)= 360 V. In the given circuit diagram, find the charge which will flow through direction 1 and 2 when switch S is closed.

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