1.

The capacity of a parallel plate capacitor is 10 muF, when the distance between its plates is 8 cm. If the distance between the plates is reduced to 4 cm, the new capacity of the parallel plate capacitor will be

Answer»

`5 mu F`
`10 mu F`
`20 MUF`
`40 muF`

Solution :Since capacitance of a parallel PLATE capacitor is INVERSELY proportional to the DISTANCE between theplates of capacitor, hence `(C.)/C = d/(d.)`
`rArr C. = C.d/(d.) = 10mu F xx (8 cm)/(4 cm) = 20 muF`


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