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The car makes a displacement of 100m towards east and then 200m towards north. Find the magnitude and direction of the resultant.A. 223,7m, `tan^(-1)(2),N` of EB. 223,7m, `tan^(-1)(2),E` of NC. 300m, `tan^(-1)(2)`, N of ED. 100m, `tan^(-1)(2)`, N of E |
Answer» Correct Answer - A `s_(1)=100hati,s_(2)=200hatj` `s=sqrt(s_(1)^(2)+s_(2)^(2)), Tan theta=(s_(2))/(s_(1))rarrN` of E |
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