InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
The ceiling of a long hall is 20 m high. What is the maximum horizontal distance that a ball thrown with a speed of 40 ms^(-1) can go without hitting the ceiling of the hall (g=10 ms^(-2)) |
|
Answer» Solution :Here `H=20 m, u=40 ms^(-1)`. Suppose the BALL is thrown at an ANGLE `theta` with the HORIZONTAL. Now `H=(u^(2) sin^(2) theta)/(2g)rArr 20=((40)^(2) sin^(2) theta)/(2XX10)` or `sin theta=0.5 "" or theta=30^(@)` Now `R=(u^(2)sin 2 theta)/(g)=((40)^(2)xx sin 120^(@))/(10)` `=((40)^(2)xx0.866)/(10)=138.56 cm` |
|