1.

The cells of emf's E_(1) and E_(2) be connector in parallel in a circuit. Let r_(1) and r_(2) be the internal resistance of the cells. Then the current through the circuit is

Answer»

`(E_(1)+E_(2))/((r_(1)+r_(2)))` 
`(E_(1)-E_(2))/((r_(1)+r_(2)))`
`(E_(1)+E_(2))/((r_(1)-r_(2)))`
`(2(E_(1)+E_(2)))/((r_(1)+r_(2)))`

ANSWER :B


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