1.

The central fringe of the interference pattern produced by the light of wavelength 6000 Å is found to shift to the position of 4th dark fringe after a glass sheet of refractive index 1.5 is introduced. The thickness of glass sheet would beA. `4.8 mu m`B. `4.2 mu m`C. `5.4 mu m `D. `3.0 mu m `

Answer» Correct Answer - B
Shift `=((mu-1)tD)/d = 3.5, omega= (3.5lambdaD)/d`
`t=(3.5lambda)/(mu-1)`
`=((3.5)(6000 xx 10^-10))/(1.5 -1)`
=`4.2 xx 10^(-6)m`
=4.2 `mu`m.


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