1.

The centre of mass of a system of two particles of masses m_(1)andm_(2) is at a distance a_(1), from mass m_(1) and at a distance a_(2) from mass m_(2) such that :

Answer»

`(a_(1))/(a_(2))=(m_(2))/(m_(1))`
`(a_(1))/(a_(2))=(m_(1))/(m_(2))`
`(a_(1))/(a_(2))=(m_(1))/((m_(1)+m_(2)))`
`(a_(1))/(a_(2))=(m_(2))/((m_(1)+m_(2)))`

Solution :SUM of MOMENTS about CENTRE of mass is zero
`therefore m_(1)(+a_(1))+m_(2)(-a_(2))=0`

`m_(1)a_(1)=m_(2)a_(2)IMPLIES (a_(1))/(a_(2))=(m_(2))/(m_(1))`


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