The centroid of ΔPQR whose vertices are P(1, –3) Q(–3, 6) and R(x, y) is (–2, 2) then value of (x + y)2 equals

The centroid of ΔPQR whose vertices are P(1, –3) Q(–3, 6) and R(x

1.	The centroid of ΔPQR whose vertices are P(1, –3) Q(–3, 6) and R(x, y) is (–2, 2) then value of (x + y)2 equals
Answer» begin{gathered}\BOXED{\begin{minipage}{11.44cm}\textsf{If the coordinates of the vertices of a triangle are \ $(x_1,\ y_1),\ (x_2,\ y_2)$ \ and \ $(x_3,\ y_3),$}\\ \\ \textsf{then the coordinates of the centroid of the triangle will be,}\\ \\ \begin{center}\LARGE \text{$\left(\dfrac{x_1+x_2+x_3}{3},\ \dfrac{y_1+y_2+y_3}{3}\right)$}\END{center}\end{minipage}}\end{gathered}Coordinates of three vertices of ΔPQR are given.\begin{gathered}\mapsto\ P(1, 1)\\ \\ \mapsto\ Q(2, 2)\\ \\ \mapsto\ R(-3, -3)\end{gathered} ↦ P(1,1)↦ Q(2,2)↦ R(−3,−3)