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The change of energy on freezing `1.00 kg` of liquid water at `0^(@)C` and1 atmisA. `236 .7 kJ kg^(-1)`B. ` 333.4kJ kg^(-1)`C. ` - 333.4kJ kg^(-1)`D. `- 236 .7 kJ kg^(-1)` |
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Answer» Correct Answer - C Enthalpy of fusion of ice `= 6.03 kJ mol^(-1)` at `0^(@)C` `:.`Enthalpy of freezing of water `= - 6.03 kJmol^(-1) `at`0^(@)C` i.e.,.Enthalpy change on freezing of 18 g ofwater at `0^(@)C =- 6.03 kJ` `:.`Enthalpy change on freezing1000 g ofwter. `= - ( 6.03)/( 18) xx 1000 =- 335 kJ ` |
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