InterviewSolution
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InterviewSolution
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The charge in Columb of Na+ ions is\left. \begin{array} { l } { \text { (A) } 96500 } \\ { \text { (B) } 4.8 \times 10 ^ { + 19 } } \\ { \text { (C) } 4.8 \times 10 ^ { - 19 } } \\ { ( D ) 1.6 \times 10 ^ { - 19 } } \end{array} \right. |
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Answer» you could think of it like this...1 Na(+) x (1 extra proton / 1 Na(+)) x (1.602x10^-19 coulombs / proton) = 1.602x10^-19 coulombs |
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