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The charge required for the reduction of 1 mole of `Cr_(2)O_(7)^(2-)` ions to `Cr^(3+)` isA. 3FB. 3 coulombC. 6FD. `2xx6.023xx10^(23)e^(-)` |
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Answer» Correct Answer - C `Cr_(2)O_(7)^(-2)rarr2Cr^(3+)` Change in O.S.=6` `therefore`Charge required = 6F |
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