The check for design capacity of channel/I-section purlin is given by(a) Mdz ≤ 1.2Zeyfy/γm0, Mdy ≤ 2.4Zezfy/γm0(b) Mdz ≤ Zezfy/γm0, Mdy ≤ 1.2Zeyfy/γm0(c) Mdz ≤ γfZeyfy/γm0, Mdy ≤ 1.2Zezfy/γm0(d) Mdz ≤ 1.2Zezfy/γm0, Mdy ≤ γfZeyfy/γm0This question was posed to me in an online quiz.My enquiry is from Purlins in chapter Design of Beams of Design of Steel Structures

The check for design capacity of channel/I-section purlin is given by(

1.	The check for design capacity of channel/I-section purlin is given by(a) Mdz ≤ 1.2Zeyfy/γm0, Mdy ≤ 2.4Zezfy/γm0(b) Mdz ≤ Zezfy/γm0, Mdy ≤ 1.2Zeyfy/γm0(c) Mdz ≤ γfZeyfy/γm0, Mdy ≤ 1.2Zezfy/γm0(d) Mdz ≤ 1.2Zezfy/γm0, Mdy ≤ γfZeyfy/γm0This question was posed to me in an online quiz.My enquiry is from Purlins in chapter Design of Beams of Design of Steel Structures
Answer» Correct option is (d) Mdz ≤ 1.2Zezfy/γm0, MDY ≤ γfZeyfy/γm0 Easy explanation: The CHECK for design capacity of channel/I-section purlin is GIVEN by Mdz ≤ 1.2Zezfy/γm0 , Mdy ≤ γyZeyfy/γm0 , where Mdz and Mdy are design moment capacity about Z and Y axes, respectively, Zez and Zeyare elastic section modulus about Z and Y axes, respectively and fy is yield stress of steel. Since in y-direction, the SHAPE factor Zp/Ze will be greater than 1.2, γf is used instead of 1.2. If 1.2 is used the onset of YIELDING under unfactored loads cannot be prevented.

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