The value of β in equation of moment capacity of plastic section for V > 0.6Vd is given by(a) ([Vd/V] -1)^2(b) (2[Vd/V] +1)^2(c) (2[Vd/V] -1)^2(d) (2[Vd/V] -1)I had been asked this question in homework.Question is taken from Design Strength of Laterally Supported Beams in division Design of Beams of Design of Steel Structures

The value of β in equation of moment capacity of plastic section for

1.	The value of β in equation of moment capacity of plastic section for V > 0.6Vd is given by(a) ([Vd/V] -1)^2(b) (2[Vd/V] +1)^2(c) (2[Vd/V] -1)^2(d) (2[Vd/V] -1)I had been asked this question in homework.Question is taken from Design Strength of Laterally Supported Beams in division Design of Beams of Design of Steel Structures
Answer» The CORRECT choice is (c) (2[Vd/V] -1)^2 To ELABORATE: The value of β in equation of moment capacity of plastic SECTION for V > 0.6Vd is given by β = (2[Vd/V] -1)^2, where Vd =design SHEAR strength as governed by web yielding or web buckling, V = factored applied shear force.

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The value of β in equation of moment capacity of plastic section for V > 0.6Vd is given by(a) ([Vd/V] -1)^2(b) (2[Vd/V] +1)^2(c) (2[Vd/V] -1)^2(d) (2[Vd/V] -1)I had been asked this question in homework.Question is taken from Design Strength of Laterally Supported Beams in division Design of Beams of Design of Steel Structures

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