1.

The circuit is shown in figure. The ratio of current i_(1) // i_(2) is

Answer»

`5//3`
`4//3`
`3//2`
`2//3`

Solution :(b) In LOOP `fgihf`,
`- 16 i_(2) + 6= 16 i_(2) = 0 implies i_(2) = (3)/(16) A`
In loop `hikjj`
`-6 + 8 - 4 (4 i_(2) - i_(1)) = 0 implies 2 2 - 4 ((3)/(4) - i_(i)) = 0`
`i_(1) = (1)/(4) A implies (i_(1))/(i_(2)) = (5)/(3)`


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