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The circuit shown consists of a switch (S), a battery (B) of emf E, a resistance R, and an inductor L. The current in the circuit at the instant the switch is closed is- (A) E/R (B) E/R(1 – e) (C) ∞ (D) 0 |
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Answer» Correct Option :- (D) 0 Explanation :- Using the equation I = I0 (1 − e−t/tL ) Put t = 0 we get I = 0 Just when the battery is closed inductor provides infinite resistance to the current flow ∴ current is zero initially. |
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