Saved Bookmarks
| 1. |
The circuit shown in Fig. contains two diodes each with a forward resistance of 50 ohm and with infinite reverse resistance. If the battery voltage is 6V, find the current through the 100 ohm resistance. |
Answer» Solution :As per given circuit, diode `D_(1)` is FORWARD BIASED and offers a resistance of 50 ohm. Diode `D_(2)` is REVERSE biased and as its corresponding resistance circuit is as SHOWN in Fig.As all the three resistances are in SERIES, the current through them is `I=(6V)/((50+150+100)W)=(6)/(300)A=0.02A` |
|