1.

The circuit shown in thefigure contains two diodeseach with a forwardresistance of 50 ohm andwith infinite backwardresistance. If the battery voltage is 6 V, the current through the 100 ohm resistance (in ampere) is

Answer»

zero
0.02
0.03
0.033

Solution : In the given circuit, diode `D_1` is forward biased while `D_2` is reverse biased. Moreover, `D_1` has a forward RESISTANCE of 50 `OMEGA`.
`THEREFORE I=6/(50+150+100)=6/300`=0.02 A
CURRENT through 100 `Omega` resistance = 0.02 A


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