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The circuit shown in thefigure contains two diodeseach with a forwardresistance of 50 ohm andwith infinite backwardresistance. If the battery voltage is 6 V, the current through the 100 ohm resistance (in ampere) is |
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Answer» zero `THEREFORE I=6/(50+150+100)=6/300`=0.02 A CURRENT through 100 `Omega` resistance = 0.02 A |
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