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The circuit shows a resistance R=0.01Omega and inductance L=3 mH connected to a conducting rod PQ of length I=2m which can side on a perfectly conducting circular arc of radius I with its centre at P. Assume that friction & gravity are absent and a constant uniform magnetic field B=0.1T exists as shown in the figure. At t=0 the circuit is switched on and simultaneously an external torque is applied on the rod so that it rotates about P with a constant angular velocity omega=2 rad/sec. Find the magnitude of this torque (in N-m) at t=0 (0.3 In2) second

Answer»


Solution :The Half of the MAXIMUM CURRENT is equal to `i_(1)=(Bomega I^(2))/(4R)` at `t=L/R In 2`
The torque at this instant` =(B^(2)omegaI^(4))/(8R)=4N-m`


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