1.

The co-ordinates of moving particle at any time t are given by x = at^(2) and y = bt^(2). The velocity magnitude of the particle :

Answer»

`2tsqrt(a^(2)-b^(2))`
`2T(a-b)`
`sqrt(a^(2)+b^(2)) `
`2tsqrt(a^(2)+b^(2))`

Solution :`V_(x)=dx/dt=2at`
`V_(y)=(DY)/(dt)=2bt`
`:. V=sqrt(V_(x)^(2) + V_(y)^(2))=sqrt(4a^(2)t^(2) + 4B^(2)t^(2))`
`=2tsqrt(a^(2)+ b^(2))`


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