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The co ordinates of the points of a line segment in the ratio 2:1 |
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Answer» Using the section formula, if a point (X,y) divides the line joining the points (X1,y1) and (X2,Y2) internally in the ratio m:n, then (x,y)=(m+nmx2+nx1,m+nmy2+ny1) Substituting (x1,y1)=(−2,1) and (x2,y2)=(1,4) and m=2,n=1 in the section formula, we get the point (2+12(1)+1(−2),2+12(4)+1(1))=(0,3) |
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