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The coeffcient of performance of a refrigerator working between `10^(@)C` and `20^(@)C` isA. 28.3B. 29.3C. 2D. Cannot be calculated

Answer» Correct Answer - A
Given , `T_(1)=273+20=293K,T_(2)=273+10=283K`
`therefore` Conefficient performance
= `(T_(2))/((T_(1)-T_(2)))=(283)/(293-283)=(283)/(10)=28.3`


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