1.

The coefficient of friction between a body and the surface of inclined plane at45^@ is 0.5. Ifg=9.8m/s^2 The acceleration of the body downwards in m/s^2 is

Answer»

`4.9/sqrt2`
`4.9sqrt2`
`19.2sqrt2`
4.9

Solution :NET ACCELERATION `a=g(a=g(sintheta-mucostheta)=9.8(SIN45^@-0.5cos45^@)=4.9/sqrt2m/s_226.(C)27(c)`


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