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The coefficient of mutual inductance of the two coils is `0.5 H`. If the current is increased from `2` to `3` `A ln 0.01 sec`. In one of them, then the induced e.m.f. in the second coil is :A. `25V`B. `50V`C. `75V`D. `100V` |
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Answer» Induced emf `=M(di)/(dt)=0.5(3-2)/(0.01)=50V` |
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